Alotaketal A

 

Alotaketal A

Organic Letters 2012, 14, 5492-5494

M. Xuan, I. Paterson, S. M. Dalby *

The retrosyntheses of Alotaketal A begins with a sequence of double oxidation of two alcohols (a primary and the other secondary) and then selective reduction of the aldehyde in presence of the ketone by using sodium triacetoxyborohydride.  This is a bold final step!  Compound 16 has the sensitive ketal group which is formed by internal cyclization and protection of compound 15.  The allylic alcohol in 15 is formed by the nucleophilic attack of lithiated 6 on lactone 14.  Lactone 14 is formed by an intermolecular HWE reaction of phosphonate 13, which comes by the coupling of acid chloride of 12 with alcohol 11.  Here, the Yamaguchi reagent (trichlorobenzoyl chloride) was used to activate the acid.  Compound 11 was prepared by the selective Johnson-Lemieux oxidation of the less-hindered alkene bond of compound 10.  Compound 10 was derived by an interesting allylic oxidation and then selective reduction procedure.  The allylic alcohol 9 gets oxidized to the ketone (at the unsaturated carbon) with simultaneous dehydration to give an a,b-unsaturated ketone (not drawn).  This is then stereoselectively reduced to the allylic alcohol 10 by using the bulky L-selectride.  The protected TBS ether in 9 came from by the reduction (and then protection) of ketone 8.  This a-hydroxyketone was prepared by Rubbotom oxidation of ketone 7 (7 was first converted to its TMS enol ether and then oxidized by using mCPBA).  Compound 7 was prepared from (R)-carvone by first chlorinating the allylic carbon (Ca(OCl)₂), then hydrolyzing it to the alcohol and then protecting it as TIPS-ether.

The intermediate 6 has the allylic iodide group, which came from the corresponding ester 5.  Ester 5 was treated with TMSCH₂MgCl which gave the double addition of the “CH₂-“ group on the ester.  It also produced a tertiary alcohol which eliminated.  Ester 5 came from a Nagao aldol reaction of chiral auxially 3 with aldehyde 2.  Aldehyde 2 is simply the oxidized form of geraniol – but it was produced in a rather round-about way.  Geraniol was first chlorinated and then reduced by LAH.  The allyl group was then oxidized to the aldehyde by MnO₂.

 

Aldingenin

 

Aldingenin

Organic Letters 2012, 14, 2168

M. T. Crimmings*, C. O. Hughes

The retrosynthesis of aldingenin begins with the deprotection of the benzyl ether and the bromoetherification of compound 13.  The bromoetherification step using 2,4,4,6-tetrabromocyclohexa-2,5-dienone (TBCO) also gave the 5-exo product (i.e. produced bromotetrahydrofuran ring) which reduced the overall yield.  The tertiary hydroxyl group in 13 was prepared by the addition of “Me^-” to ketone 12 by using MeLi along with CeCl₃.LiCl.  Here the attacking reagent is presumably the less nucleophilic “MeCeCl₂” with additional coordination with LiCl.   When isopropylidiene phosphorane was used on aldehyde 10, the prenyl product 12 could not be prepared. So, the prenyl group in 12 was prepared by a cross-metathesis reaction between alkene 11 and 2-methyl-2-butene (also served as the solvent!).  This is a really neat trick because alkene 11 was prepared from aldehyde 10 by using a variation of “Wittig-reaction” – Nysted conditions (Zn₃Br₂(CH₂)₂, BF₃.OEt₂, THF).  Again, this was necessitated by the failure of traditional Wittig and Tebbe reagents in this step, which I suspect might be due to the presence of a keto group in addition to the aldehyde.  Keto-aldehyde 10 was prepared by a double Swern oxidation step of alcohol 9, which, in turn was prepared from compound 8.  In this step, the cyclopentadienyl ketal got hydrolyzed to reveal the diol which immediately cyclized with the internal ketone group.  Compound 8 is an alpha-hydroxy ketone, and is formed by the nucleophilic attack of dithiane 7’ on aldehyde 7.  This is the classic “umpulong” chemistry and it required the presence of CeCl₃.LiCl along with the base (nBuLi).  The Crimmins group also came up with a method to dry CeCl₃ – which was crucial in this step.  The aldehyde group in 7 came by the Ley oxidation of alcohol 6, which was prepared from diol 5.  syn-Diol 5 was prepared by a hydroxyl-directed stereoselective dihydroxylation step employing OsO₄ along with TMEDA – which is quite noteworthy.  Alkene 4 is ripe for a RCM disconnection to reveal bis-alkene 3, which came from the removal of the chiral auxiliary from 2. Compound 2 was prepared by a “anti-selective-aldol” reaction between dibenzyl acetal 1’ and the chiral thiazolidinone 1.

Unfortunately, at the end of the synthesis the spectra of the natural and the synthetic material did not match! That’s not what you want to see at the end of the synthesis – but a great job by the synthetic chemist nevertheless – after all this was the structure they proposed!  So, the structure of the naturally isolated material needs to be elucidated correctly.